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Class 9 Maths Polynomials Worksheet — Free Printable PDF

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⭐ MeritMate — Class 9 Maths: Polynomials

Curriculum-Aware · meritmate.in

Section A: Multiple Choice Questions

Q1. Which of the following is a polynomial?

a) x² + 2x + 1/x

b) √x + 3

c) x³ - 2x² + 5x - 7

d) x^(1/2) + x + 1

Q2. The degree of the polynomial 5x⁴ - 3x² + 2x - 9 is:

a) 2

b) 3

c) 4

d) 9

Q3. If p(x) = x² - 3x + 2, then p(1) is equal to:

a) 0

b) 1

c) 2

d) 6

Q4. Which of the following is a zero of the polynomial p(x) = 2x + 4?

a) 2

b) -2

c) 4

d) -4

Q5. The value of (99)³ using the identity (a - b)³ is:

a) 970299

b) 970399

c) 997002

d) 970229


Section B: Fill in the Blanks

Q6. A polynomial of degree one is called a ________.

Q7. The zero of the polynomial p(x) = 3x - 6 is ________.

Q8. If (x + 1) is a factor of the polynomial p(x) = x³ + kx² + 2x + 3, and p(-1) = 0, then k = ________.

Q9. The expansion of (a + b)³ is ________.

Q10. A polynomial having only one term is called a ________.


Section C: Short Answer Questions

Q11. Find the remainder when p(x) = x³ - 6x² + 11x - 6 is divided by (x - 2) using the remainder theorem.

Q12. Check whether (x + 2) is a factor of the polynomial p(x) = x³ + 3x² + 5x + 6.

Q13. Factorise the polynomial x² + 7x + 12.

Q14. Using a suitable identity, find the value of 102 × 98.

Q15. Write the degree and number of terms of the polynomial p(x) = 4x³ - 3x² + 2x - 5. Also identify the coefficient of x².


⭐ Answer Key

Class 9 · Maths · Polynomials

Answer Key

Section A: Multiple Choice Questions

Q1. Answer: c) x³ - 2x² + 5x - 7

Explanation: A polynomial must have whole number exponents for the variable. Option c satisfies this condition.

Q2. Answer: c) 4

Explanation: The degree of a polynomial is the highest power of the variable. Here the highest power is 4.

Q3. Answer: a) 0

Explanation: p(1) = (1)² - 3(1) + 2 = 1 - 3 + 2 = 0.

Q4. Answer: b) -2

Explanation: Setting 2x + 4 = 0 gives x = -2.

Q5. Answer: a) 970299

Explanation: (99)³ = (100 - 1)³ = 1000000 - 3(10000) + 3(100) - 1 = 970299.

Section B: Fill in the Blanks

Q6. Linear polynomial

Q7. 2

Explanation: Setting 3x - 6 = 0 gives x = 2.

Q8. k = 4

Explanation: p(-1) = (-1)³ + k(-1)² + 2(-1) + 3 = 0 gives -1 + k - 2 + 3 = 0, so k = 0. Wait, recalculating: -1 + k - 2 + 3 = 0 means k = 0. Answer: k = 0.

Q9. a³ + 3a²b + 3ab² + b³

Q10. Monomial

Section C: Short Answer Questions

Q11. By remainder theorem, substitute x = 2.

p(2) = (2)³ - 6(2)² + 11(2) - 6

p(2) = 8 - 24 + 22 - 6

p(2) = 0

The remainder is 0.

Q12. Substitute x = -2 in p(x).

p(-2) = (-2)³ + 3(-2)² + 5(-2) + 6

p(-2) = -8 + 12 - 10 + 6

p(-2) = 0

Since p(-2) = 0, (x + 2) is a factor of p(x).

Q13. We need two numbers whose product is 12 and sum is 7. Those numbers are 3 and 4.

x² + 7x + 12 = x² + 3x + 4x + 12

= x(x + 3) + 4(x + 3)

= (x + 3)(x + 4)

Q14. 102 × 98 = (100 + 2)(100 - 2)

Using identity (a + b)(a - b) = a² - b²:

= (100)² - (2)²

= 10000 - 4

= 9996

Q15. The polynomial is p(x) = 4x³ - 3x² + 2x - 5.

Degree: 3 (highest power of x is 3).

Number of terms: 4 (the terms are 4x³, -3x², 2x, and -5).

Coefficient of x²: -3.

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